Area of the shaded segment=

ANSWERS

2015-11-09 21:27:31

Alright, since the radius is 6, pi(6)^2=36pi is your area. Since 60/360=1/6, that means the overall section is 36pi/6=6pi. Since this can be made 6 times, AB = 6 as 36/6=6 and OAB is equilateral, making the area of that sqrt(3)*(6^2)/4 = 9sqrt(3). Therefore, the area of the shaded segment is 6pi-9sqrt(3)

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