Mathematics
NhGrace
2017-08-22 08:39:00
Solve Sine inverse x +sine inverse 2x = π/3 Please solve it faster..
ANSWERS
Goering251
2017-08-22 13:10:11

arcsin x + arcsin 2x = π/3 arcsin 2x =  π/3 - arcsin x sin[arcsin 2x] = sin[π/3 - arcsin x] (remember the left side is like sin(a-b) 2x = sinπ/3 cos(arcsin x)-cosπ/3 sin(arc sinx) 2x = √3/2 . cos(arcsin x) - (1/2)x) but cos(arcsin x) = √(1-x²)===>2x = √3/2 .√(1-x²)  - (1/2)x) Reduce to same denominator: (4x) = √3 .√(1-x²)  - (x)===>5x = √3 .√(1-x²) Square both sides==> 25x²=3(1-x²) 28 x² = 3 & x² = 3/28 &  x =√(3/28)

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