If 72 out of 200 individuals express the recessive phenotype, what percentage will be homozygous dominant? Please Help!

ANSWERS

2017-08-14 20:29:41

If the recessive phenotype has the genotype nn, then the frequency of nn in the population is 72/200 = 0.37. If the frequency of nn = 0.37, then the frequency of n is sqrt(0.37)=0.6083. According to the Hardy-Weinberg equation #1, the frequency of the dominant allele, N, is 1 - 0.6083 = 0.3917. Therefore, the frequency of the dominant homozygous, NN = 0.3917↑2 = 0.15342889 or 15.342889%

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