Mathematics
OlgaVosika
2017-08-13 12:33:45
How to solve step by step
ANSWERS
ethington3
2017-08-13 17:49:57

∫tan²4x.dx=4∫tan²xdx but tan²x =sec²x-1 ===>4∫(sec²x-1)dx = 4[∫sec²dx-∫dx] ===>4∫sec²xdx-4∫dx=====> 4tanx-4x +c

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