Mathematics
OliveBucholtz395
2017-08-12 02:41:00
Find the critical numbers sin^2x+cosx 0 < x< 2pi
ANSWERS
jacobrarey1
2017-08-12 03:49:31

[latex]f sin^2(x)+cos(x)iff [sin(x)]^2+cos(x)\\ -----------------------------\\ cfrac{dy}{dx}=2sin(x)cos(x)-sin(x)implies 0=2sin(x)cos(x)-sin(x) \\\ 0=sin(x)[2cos(x)-1]implies egin{cases} 0=sin(x)\ sin^{-1}(0)=measuredangle x\ pi \ ----------\ 0=2cos(x)-1\\ frac{1}{2}=cos(x)\\ cos^{-1}left( frac{1}{2} ight)=measuredangle x\\ frac{pi }{3},frac{5pi }{3} end{cases}[/latex]

ADD ANSWER