Chemistry
Chott575
2015-11-03 19:12:15
Given 7.55 g of butanoic acid and excess ethanol, how many grams of ethyl butyrate would be synthesized, assuming a complete 100% yield?
ANSWERS
Aswathy
2015-11-03 20:05:39

mC3H7COOC2H5: (12×6)+(1×12)+(16×2) = 116 g/mol mC3H7COOH: (12×4)+(1×8)+(16×2) = 88 g/mol 88g....................................................116g C3H7COOH + C2H5OH ---> C3H7COOC2H5 + H2O 7,55g..................................................X X = (116×7,55)/88 X = 9,952g of ethyl butyrate

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