The length of a rectangle is twice its width, the perimeter is 126 fee

ANSWERS

2015-10-30 08:18:28

The equation for perimeter is 2l + 2w = P. Therefore, 2l + 2w = 126 Since length is twice the width, l = 2w and substitute; 2l + l = 126; 3l = 126; l = 42 Plug the l in to find w; 2(42) + 2w = 126; 84 + 2w = 126; 2w = 42; w = 21 Length = 42 Width = 21

2015-10-30 08:19:43

Formula for perimeter: 2l + 2w. Therefore, 2l + 2w = 126. We know that ==> l = 2w Substitute: 2(2w) + 2w = 126 Solve: 4w + 2w = 126 Like Terms: 6w = 126 Divide: w = 21 The width is 21. Substitute the value of the width back into the equation to solve. l = 2w. l = 2(21) l = 42 If you substitute them back, the answer is 126. 2(42) + 2(21) = 126. The length is 42. The width is 21.

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