Find the area of a sector with a central angle of 102 degrees and a radius of 15.7 millimeters.
ANSWERS
2020-04-17 19:43:23
A = .5 r^2 theta Theta must be in radians A = .5 (15.7)^2 (102)(pi/180) A= 219 mm^2
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A = .5 r^2 theta Theta must be in radians A = .5 (15.7)^2 (102)(pi/180) A= 219 mm^2